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## Homework Statement

A certain die is weighted such that probabilities of showing a 1, 2, 3, 4, 5, and 6 are

(6/34),

(8/34),

(5/34),

(3/34),

(8/34),

and

(4/34)

A) If two such dice are thrown, and you are told that the sum of the two is 10 or larger. What is the probability that the result was a pair of 5's?

B) How many times would you have to throw this die to have the probability of throwing a 2 exceed 40 percent?

## Homework Equations

## The Attempt at a Solution

A) For this the possible outcomes for a sum of 10 or greater are:

4-6

5-5

5-6

6-4

6-5

6-6

Getting rid of duplicates, since order doesn't matter there is a 1/4 chance it's double fives. I multiplied this by (8/34)(8/34) and got a probability of .01384

B) For this I used the equation

Probability = Successful outcomes/Total number of outcomes

so .4 = (8/34)/n

solving for n I get .588, which doesn't make sense.

I'm just learning statistics, so if anything I tried to do offends you mathematically, I'm very sorry!